Gas Junkie - Gasoline Prices Questions

Question: Word problem.. Please help!?

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Answer #1:

well unless you just want it as a ratio you need to know the distance traveled and the cost of gasoline.

to find your answer as a ratio:

mpg of sedan = 32
mpg of van = 18
you can find out how much more efficient the sedan is by dividing the sedan's mpg by the van's mpg
32/18 = 1.777778
the van will use 1.777777778 gallons of gas for every gallon the sedan uses so it will cost that much more. so your answer is

the van will cost (1.777777778 x the price of gasoline for the sedan) - price of gasoline for the sedan

Answer #2:

You don't have a starting point or end point, no mileage is given, and no price is given for the gas at all, just an additional 40 cents a gallon. We need more info to do this problem, sorry.

Answer #3:

Let x = $ price per gallon of gasoline; y = distance to be driven.

Amount more to pay if they take the van:
= x(y/18) - x(y/32)
= (16xy - 9xy)/288
= (7xy)/288

With 40-cent increase, if they take the:
Van:
= (x + $0.40)(y/18)
= (xy + $0.40y)/18

Sedan:
= (x + $0.40)(y/32)
= (xy + $0.40y)/32

Difference (if they take the van instead of the sedan):
= (xy + $0.40y)/18 - (xy + 0.40y)/32
= (16xy + $6.40y - 9xy - $3.60y)/288
= (7xy + $2.80y)/288 OR (7[xy + $0.40])/288

Answer: as stated above





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